9.
Maps & Sets
Written by Irina Galata
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A map is an unordered collection of pairs, where each pair is comprised of a key and a value.
As shown in the diagram above, keys are unique. The same key can’t appear twice in a map, but different keys may point to the same value. All keys have to be of the same type, and all values have to be of the same type.
Maps are useful when you want to look up values by means of an identifier. For example, the table of contents of this book maps chapter names to their page numbers, making it easy to skip to the chapter you want to read.
How is this different from an array? With an array, you can only fetch a value by its index, which has to be an integer, and all indexes have to be sequential. In a map, the keys can be of any type and are generally in no particular order.
Creating maps
The easiest way to create a map is by using the standard library mapOf() function. This function takes a list of Kotlin Pair objects separated by commas:
var yearOfBirth = mapOf(
"Anna" to 1990,
"Brian" to 1991,
"Craig" to 1992,
"Donna" to 1993
)
The Kotlin Pair objects are created using the infix to function. Note that Map<K, V> is an interface, which you’ll learn more about later on. The concrete type that is created depends on which standard library function is called. The mapOf() function returns an immutable map of fixed size.
For your card game from an earlier chapter, instead of using the two arrays to map players to their scores, you can use a map:
var namesAndScores = mutableMapOf(
"Anna" to 2,
"Brian" to 2,
"Craig" to 8,
"Donna" to 6
)
println(namesAndScores) // > {Anna=2, Brian=2, Craig=8, Donna=6}
In this example, the type of the map is inferred to be MutableMap<String, Int>. This means namesAndScores is a map with strings as keys and integers as values, that is, a map from strings to integers.
When you print the map, you see there’s generally no particular order to the pairs. Remember that, unlike arrays, maps are not guaranteed to be ordered!
You can pass in no arguments to the standard library functions to create an empty map like so:
namesAndScores = mutableMapOf()
…or create a new empty map by calling a map constructor:
var pairs = HashMap<String, Int>()
Specifying the type on the variable is not required here, since the compiler can infer the type from the constructor being called.
Note: If you’re following along, you’ll need to add the import,
import java.util.HashMap, to the top of the file to useHashMap.
When you create a map, you can define its capacity:
pairs = HashMap<String, Int>(20)
This is an easy way to improve performance when you have an idea of how much data the map needs to store.
Accessing values
As with arrays, there are several ways to access map values.
Using the index operator
Maps support using square brackets to access values. Unlike arrays, you don’t access a value by its index but rather by its key. For example, if you want to get Anna’s score, you would type:
namesAndScores = mutableMapOf(
"Anna" to 2,
"Brian" to 2,
"Craig" to 8,
"Donna" to 6
)
// Restore the values
println(namesAndScores["Anna"])
// > 2
namesAndScores["Greg"] // null
Using properties and methods
In addition to using indexing, you can also use the get() function to access a value:
println(namesAndScores.get("Craig"))
// > 8
namesAndScores.isEmpty() // false
namesAndScores.size // 4
Modifying mutable maps
It’s easy enough to create maps and access their contents — but what about modifying them? You’ll need a mutable map to do so.
Adding pairs
Bob wants to join the game. Take a look at his details before you let him join:
val bobData = mutableMapOf(
"name" to "Bob",
"profession" to "CardPlayer",
"country" to "USA"
)
bobData.put("state", "CA")
bobData["city"] = "San Francisco"
Mini-exercise
Write a function that prints a given player’s city and state.
Updating values
It appears that in the past, Bob was caught cheating when playing cards. He’s not just a professional — he’s a card shark! He asks you to change his name and profession so no one will recognize him.
bobData.put("name", "Bobby") // Bob
bobData["profession"] = "Mailman"
val pair = "nickname" to "Bobby D"
bobData += pair
println(bobData)
// > {name=Bobby, profession=Mailman, country=USA, state=CA, city=San Francisco, nickname=Bobby D}
Removing pairs
Bob — er, sorry — Bobby, still doesn’t feel safe, and he wants you to remove all information about his whereabouts:
bobData.remove("city")
bobData.remove("state", "CA")
Iterating through maps
The for-in loop works when you want to iterate over a map. But since the items in a map are pairs, you need to use a destructuring declaration:
for ((player, score) in namesAndScores) {
println ("$player - $score")
}
// > Anna - 2
// > Brian - 2
// > Craig - 8
// > Donna - 6
for (player in namesAndScores.keys) {
print("$player, ") // no newline
}
println() // print a newline
// > Anna, Brian, Craig, Donna,
Running time for map operations
In order to be able to examine how maps work, you need to understand what hashing is and how it works. Hashing is the process of transforming a value — String, Int, Double, Boolean, etc — to a numeric value, known as the hash value. This value can then be used to quickly look up the values in a hash table.
println("some string".hashCode())
// > 1395333309
println(1.hashCode())
// > 1
println(false.hashCode())
// > 1237
Sets
A set is an unordered collection of unique values of the same type. This can be extremely useful when you want to ensure that an item doesn’t appear more than once in your collection, and when the order of your items isn’t important.
Creating sets
You can declare a set explicitly by using the standard library setOf() function:
val names = setOf("Anna", "Brian", "Craig", "Anna")
println(names)
// > [Anna, Brian, Craig]
val hashSet = HashSet<Int>()
Set from arrays
Sets can be created from arrays. Consider this example:
val someArray = arrayOf(1, 2, 3, 1)
var someSet = mutableSetOf(*someArray)
println(someSet) // > [1, 2, 3]
Accessing elements
You can use contains() to check for the existence of a specific element:
println(someSet.contains(1))
// > true
println(4 in someSet)
// > false
for (number in someSet) {
println(number)
}
Adding and removing elements
You can use add() to add elements to a set. If the element already exists, the method does nothing.
someSet.add(5)
val removedOne = someSet.remove(1)
println(removedOne) // > true
println(someSet)
// > [2, 3, 5]
Running time for set operations
Sets have a very similar implementations to those of maps, and they also require the elements to have hash values. The HashSet running time of all the operations is identical to those of a HashMap.
Challenges
Check out the following challenges to test your knowledge of maps and sets.
1. val map1: Map<Int to Int> = emptyMap()
2. val map2 = emptyMap()
3. val map3: Map<Int, Int> = emptyMap()
val map4 = mapOf("One" to 1, "Two" to 2, "Three" to 3)
4. map4[1]
5. map4["One"]
6. map4["Zero"] = 0
7. map4[0] = "Zero"
val map5 = mutableMapOf(
"NY" to "New York",
"CA" to "California"
)
8. map5["NY"]
9. map5["WA"] = "Washington"
10. map5["CA"] = null
fun mergeMaps(
map1: Map<String, String>,
map2: Map<String, String>
): Map<String, String>
fun occurrencesOfCharacters(text: String): Map<Char, Int>
fun isInvertible(map: Map<String, Int>): Boolean
val nameTitleLookup: Map<String, String?> = mutableMapOf(
"Mary" to "Engineer",
"Patrick" to "Intern",
"Ray" to "Hacker"
)
Key points
- A map is an unordered collection of key-value pairs.
- The keys of a map are all of the same type, and the values are all of the same type.
- Use indexing to get values and to add, update or remove pairs.
- If a key is not in a map, lookup returns
null. - Built-in Kotlin types such as
String,Int,Doublehave efficient hash values out of the box. - Use
HashMap<K, V>for performance critical code. - Sets are unordered collections of unique values of the same type.
- Sets are most useful when you need to know whether something is included in the collection or not.
Where to go from here?
Now that you’ve learned about collection types in Kotlin, you should have a good idea of what they can do and when you should use them. You’ll see them come up as you continue on in the book.